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Peak versus RMS

Why can a high transient have a low RMS?

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Peak versus RMS

Why can a high transient have a low RMS?

0.50 ×
100 ms
4 ms excerpt of a 1 kHz sine-10101234Time (ms)
4 ms excerpt of a 1 kHz sine
Example signal
Sample Peak
-6.02 dBFS
RMS
-9.03 dBFS
Peak − RMS difference
3.01 dB

A steady sine has RMS = Peak / √2, or 3.01 dB below Peak. Extending the window by whole periods does not change its RMS.

Peak and RMS use the same digital reference. A single 2 ms pulse: a longer window lowers RMS, while Peak stays the same. This is not a true-peak meter or the native band algorithm.

How to read this experiment

The lab does not claim to reproduce the native 20-band algorithm. Peak and RMS are not loudness or THD.

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